Question

calculati.aflati discriminantul

5x²+9x+4=0

Answer 1

Δ=$b^{2} -4ac$
a=5
b=9
c=4
Δ=$9^{2} -4*5*4=81-80=1$
[tex] x_{1} = \frac{-b+ \sqrt{delta} }{2a} = \frac{-9+1}{10} = \frac{-8}{10} =- \frac{4}{5} \\ x_{2} = \frac{-b- \sqrt{delta}}{2a} = \frac{-9-1}{10} =-1[/tex]