Question

calculati aplicand formulele ​

Answer 1

Explicație pas cu pas:

$(x - 1)(x + 1) = {x}^{2} - {1}^{2} = {x}^{2} - 1 \ \ \\ (x - 2)(x + 2) = {x}^{2} - {2}^{2} = {x}^{2} - 4 \ \ \\ (x - 3)(x + 3) = {x}^{2} - {3}^{2} = {x}^{2} - 9 \ \ \\ (x - 4)(x + 4) = {x}^{2} - {4}^{2} = {x}^{2} - 16 \\ (x - 5)(x + 5) = {x}^{2} - {5}^{2} = {x}^{2} - 25 \\ (x - 6)(x + 6) = {x}^{2} - {6}^{2} = {x}^{2} - 36$

Answer 2

Răspuns:

x−1)(x+1)=x2−12=x2−1  (x−2)(x+2)=x2−22=x2−4  (x−3)(x+3)=x2−32=x2−9  (x−4)(x+4)=x2−42=x2−16(x−5)(x+5)=x2−52=x2−25(x−6)(x+6)=x2−62=x2−36