Question

calculati aria patratului cu latura de 2radical din12+radical3

Answer 1

Haide sa simplificam putin latura patratului
$2 \sqrt{12} + \sqrt{3} \\ 2 \times 2 \sqrt{3} + \sqrt{3} \\ 5 \sqrt{3}$
$aria = {l}^{2} = {(5 \sqrt{3}) }^{2} = 75 \: u.a$
u.a = unitati de arie, tu pui cm^2 sau m^2 etc.

Answer 2

[tex]\it \ell =2\sqrt{12}+\sqrt3=2\sqrt{4\cdot3}+\sqrt3 =2\cdot2\sqrt3+\sqrt3=5\sqrt3\ cm \\ \\ \mathcal{A} =\ell^2 =(5\sqrt3)^2=25\cdot3=75 cm^2[/tex]