Question

Calculati aria unui patrat care are perimetrul egal cu 24a²b³c, unde a,b,c ∈ N stelat.

Answer 1

$P=24a ^{2} b ^{3} c \\ P=4l \Rightarrow 4l=24a^{2}b^{3}c \Rightarrow l=6a^{2}b^{3}c. \\ \\ A=l^{2}=(6a^2b^3c)^2=\boxed{36a^4b^6c^2}.$

Answer 2

P patrat=24·a²·b³·c
P patrat=4l
⇒4l=24·a²·b³·c/:4;
⇒l=6·a²·b³·c;
⇒A patrat=l²
⇒A patrat=[6·a²·b³·c]²
⇒A patrat=6²·a⁴·b⁶·c²;
⇒A patrat=36·a⁴·b⁶·c²;