Question

calculati b)9^5-(3^5)^2+8^4-(2^4)^3
c)2^7:4^3+3^3×27:3^5+(3^1×2^4-4^2):2^3
va roggg​

Answer 1

b) 9^5-(3^5)^2+8^4-(2^4)^3 =

(3^2)^2 - 3^10 + (2^3)^4 - 2^12 =

3^10 - 3^10 + 2^12 - 2^12 =

0

c) 2^7:4^3+3^3×27:3^5+(3^1×2^4-4^2):2^3 =

2^7 : (2^2)^3 + 3^3 × 3^3 : 3^5 + (3 × 2^4 - 2^4) : 2^3 =

2^7 : 2^6 + 3^6  :3^5 + (2 × 2^4) : 2^3 =

2 + 3 + 2^5 : 2^3 =

2 + 3 + 2^2 =

2 + 3 + 4 =

9