Question

Calculati:
c) [(14^2-13^2):27-2^0]x2+2018^0​

Answer 1

[(14^2-13^2):27-2^0]x2+2018^0=​

{[(14-13)x(14+13)]:27-1}x2+1=

[(1x27):27-1]x2+1=

(27:27-1)x2+1=

(1-1)x2+1=

0x2+1=

0+1=

1