Question

calculați c) 5⁵¹÷(5⁵⁸÷5⁹), d)7⁹÷(7÷7³×7⁴), e )(2¹¹×2²⁴)÷(2¹³÷2²², ,f) (2×2²×.....×2¹⁰)÷2⁵³​ vă rog ajutațimă

Answer 1

Răspuns:

$c) {5}^{51} \div ( {5}^{58} \div {5}^{9}) < = > {5}^{51} \div ({5}^{58 - 9})< = > {5}^{51} \div {5}^{49} = {5}^{2} = 25. \\ d) {7}^{9}\div(7 \div {7}^{3} \times {7}^{4}) < = > {7}^{9} \div ( {7}^{ 1 - 3} \times {7}^{4} ) < = > {7}^{9} \div ( {7}^{ - 2} \times {7}^{4} < = > {7}^{9} \div {7}^{ - 8} < = > {7}^{9 - ( - 8)} < = > {7}^{9 + 8} = {7}^{17} \\ e)( {2}^{11} \times {2}^{24}) \div ( {2}^{13} \div {2}^{22}) < = > ( {2}^{11 + 24}) \div ( {2}^{13 - 22}) < = > {2}^{35} \div {2}^{ - 9} < = > {2}^{35 - ( - 9)} < = > {2}^{35 + 9} = {2}^{44}. \\ f)( {2}^{1} \times {2}^{2} \times ..... \times {2}^{10} < = > ({2}^{ 1+ 2 + .... + 10} ) \div {2}^{53} < = > {2}^{ \frac{10 \times (10 + 1)}{2} }) \div {2}^{53} < = > ( {2}^{ 5 \times 11}) \div {2}^{53} < = > {2}^{55} \div {2}^{53} < = > {2}^{2} = 4.$

Explicație pas cu pas:

Sper că te-am ajutat.

Answer 2

Răspuns:

c) 5⁵¹÷(5⁵⁸÷5⁹)=

5⁵¹:5⁵⁸⁻⁹=

5⁵¹⁻⁴⁹=

5²=

25

d)7⁹÷(7×7³×7⁴)=

7⁹:7¹⁺³⁺⁴=

7⁹⁻⁸=

7

e )(2¹¹×2²⁴)÷(2¹³×2²²)=

2¹¹⁺²⁴:2¹³⁺²²=

2³⁵⁻³⁵=

1

f) (2¹×2²×.....×2¹⁰)÷2⁵³​

suma lui gauss pentru exponenti

1+2+...+10=10×11:2=55

2⁵⁵⁻⁵³=

2²=

4