Matematică, întrebare adresată de Sami341, 9 ani în urmă

Calculati c.m.m.d.c.si c.m.m.m.c al numerelor a)48si144 b)231si 693. c ) 1890 si2268. d) 372 ,360 si 900

Răspunsuri la întrebare

Răspuns de iamale47
42
a)
48=2⁴•3
144=2⁴•3²
—————
c.m.m.d.c.=2⁴=16
c.m.m.m.c.=2⁴•3²=144

b)
231=3•7•11
693=3²•7•11
——————–
c.m.m.d.c.=3•7•11=231
c.m.m.m.c.=3²•7•11=693

c)
1890=2•3³•5•7
2268=2²•3⁴•7
——-—————–
c.m.m.d.c.=2•3³•7=378
c.m.m.m.c.=2²•3⁴•5•7=11340

d)
372=2²•3•31
360=2³•3²•5
900=2²•3²•5²
——————–
c.m.m.d.c.=2²•3=12
c.m.m.m.c.=2³•3²•5²•31=55800
Răspuns de Utilizator anonim
3
a)48=2^4×3
144=2^4×3^2
c.m.m.d.c
(48,144)=48
c.m.m.m.c
[48,144]=144
b)231=3×7×11
693=3^2×7×11
c.m.m.d.c
(231,693)=231
c.m.m.m.c
[231,693]=693
c)372=3×2^2×31
360=2^3×3^2×5
900=2^2×3^2×5^2
c.m.m.d.c
(372,360,900)=12
c.m.m.m.c
[372,360,900]=55800
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