Question

Calculati c.m.m.d.c si c.m.m.m.c pentru urmatoarele perechi de numere: 4 si 12,
10 si 15,5 si 6,11 si 8,9si 18,14 si 21,12 si 7,15 si 30,22 si 33,4 si 9,25 si 75,9 si 15,6 si 25

Answer 1

4;12
4=2²
12=2²·3
c.m.m.m.c.=2²·3=12
c.m.m.d.c=2²=4

10;15
10=2·5
15=3·5
c.m.m.m.c.=2·3·5=30
c.m.m.d.c.=5

5;6
5=1·5
6=2·3
c.m.m.m.c.=2·3·5=30
c.m.m.d.c.= 1

11;8
11=1·11
8=2³
c.m.m.m.c.=2³·11=88
c.m.m.d.c.=1


9;18
9=3²
18=2·3²
c.m.m.m.c.=2·3²=18
c.m.m.d.c.=3²=9

14;21
14=2·7
21=3·7
c.m.m.m.c.=2·3·7=42
c.m.m.d.c.=7

12;7
12=2²·3
7=1·7
c.m.m.m.c.=2²·3·7=84
c.m.m.d.c.=1

15;30
15=3·5
30=2·5·3
c.m.m.m.c.=2·3·5=30
c.m.m.d.c.=3·5=15

22;33
22=2·11
33=3·11
c.m.m.m.c.=2·3·11=66
c.m.m.d.c.=11

4;9
4=2²
9=3²
c.m.m.m.c.=2²·3²=36
c.m.m.d.c.=1

25;75
25=5²
75=3·5²
c.m.m.m.c.=3·5²=75
c.m.m.d.c.=5²=25

9;15
9=3²
15=3·5
c.m.m.m.c.=3²·5=45
c.m.m.d.c.=3

6;25
6=2·3
25=5²
c.m.m.m.c.=2·3·5²=30
c.m.m.d.c.=1