Question

Calculati (calcul algebric) :
a. (2x+1) * (2x-1) - (2x+1) * (2x+1) = ?
b. (x-2) * (x-3) - (x-1) * (x-5) = ?
c. (x-1) * (x-3) - (x-2) la puterea a -doua = ?
d. (x+2) * $x^{2}$ -x+3) - (x+1) * ( $x^{2}$+2x-5) = ?

p.s: vreau rezolvari cat mai detaliate, va rog! 

Answer 1

a. (2x+1)(2x-1-2x-1)=(2x+1)(-2)=-4x-2
b. $(x-2)(x-3)-(x-1)(x-5)=x^2-5x+6-x^2+6x-5=x+1$
c. $(x-2)^2-1-(x-2)^2=-1$
d. $(x+1)(x^2-x+3)+x^2-x+3-(x+1)(x^2+2x-5)=$
$=(x+1)(-3x+8)+x^2-x+3=$
$=-3x^2-3x+8x+8+x^2-x+3=-2x^2+4x+11$