Question

calculati caldura de reactie pentru procesul:
C2H6(g)+7/2O2(g)=2CO2(g)+3H2O(g) stiind ca ΔH°f(c2h6(g))= -84,44 kj/mol, ΔH°f(CO2(g))= -396kj/mol, ΔH°f(h2o(g))= -241,8kj/mol

Answer 1

C2H6(g) + 7/2O2(g)  = 2CO2(g) + 3H2O(g)

stim ca:

ΔHr = Suma caldurilor de formare a Produsilor de reactie - Suma caldurilor de formare a Reactantilor

=> ΔHr = [2xH°f(CO2(g) + 3xH°f(H2O)(g)] - [H°f(C2Hh6)(g) + 0]

substantele simple gen O2 au H°f = 0

=> ΔHr = [2x(-396) + 3x(-241,8)] - (-84,44)

=> ΔHr = -1432,96 kJ/mol