Question

Calculati cantitatea in moli de hidroxid de sodiu care neutralizeaza total 500g solutie HCl de C (concentratie)=36,5%
Urgent,va rog ajutati-ma!!!

Answer 1

NaOH+HCl=H2O+NACl
c=md/ms*100
36,5/100=md/500
md=500*36,5/100⇒md=182,5
$M_{HCl}=1+35,5=36,5g/mol$
$M_{NaOH}=23+16+1=40g/mol$
Notam sub NaOH necunoscuta x
x=40*182,5/36,5
x=200 g
n=m/M
n=200/40⇒n=5 moli NaOH