Question

calculati cantitatea moli de fier necesara in reactia cu 30 g solutie AgNO3 de concentratie 17 la suta URGENT VA ROG DAU COROANA

Answer 1

56g     2*170g

Fe + 2AgNO3--> Fe(NO3)2+2Ag

m Fe       5,1g

M AgNO3= A Ag+ A N+ 3*A O=108+14+3*16=170g/mol

MFe=56 g/mol

C%=md*100/ms=>md=ms*C/100=>md=30*17/100=5,1 g

mFe=(5,1*56)/2*170=0,84 g

nFe=mFe/M Fe=0,84/56=0,015 moli Fe

Succes!