Question

Calculati cati moli si cati atomi se gasesc in : 460g Na, 0,5kg k, 120kgC, 1700gAg .
23 23
In cate g si in cati moli se gasesc : 12,044x10 atomi de Zn, dar in 24,22 x10 atomi de Al ?

va rog mult,e la tema si is planta de venetia
si dc nu trimit la timp tema,profa o suna pe maicamea.........va rooooog

Answer 1

Răspuns:

Explicație:

n= 460g : 23g/moli= 20moli Na

1mol de atomi Na------------6,022.10²³atomi   Na

20 moli------------------------------x

x= 20  . 6,022.10²³= 120,44 .10²³atomi Na

0,5kg= 500g K

n= 500g : 39g/moli= 12,82 moli K

1mol K---------6,022.10²³atomi K

12,82 moli--------------x

x= 12,82 ; 6,022.10²³=77,205 atomi K

120kg=120000g C

n= 120000g : 12g/moli= 10000moli C

1mol C-------------6,022.10²³qatomi C

10000moli------------------x

x= 10000 . 6,022.10²³ = 60220.10²³atomi C

n= 1700g : 108g/moli=15,74 moli Ag

1mol Ag------------6,022.10²³atomi Ag

15,74 moli------------------x

x= 15,74 . 6,022.10²³=9 4,79.10²³atomi Ag

n= 12,044.10²³ : 6,022.10²³= 2moli Zn

m = n . M

m= 2moli  . 65g/moli = 130g Zn

n= 24,22 .10²³: 6,022.10²³=4moli Al

m= 4moli . 27g/moli = 108 g Al