Question

Calculati ce masa are procesul de reactie solid obtinut in urma descompunerii a 2 moli de CuCO3​

Answer 1

Răspuns:

CuCO3 → CuO + CO2

M(CuCO3) = 64 + 12 + 3 x 16 = 76 + 48 = 124 g/mol

M(CuO) = 64 + 16 = 80 g/mol

124 g CuCO3................80 g CuO

2 x 124 g CuCO3..........x g CuO

x = 2 x 124 x 80 / 124 = 2 x 80 = 160g CuO