Question

Calculati ce volum ocupa in c.n.:
a) 1g N2;
b) 1g NH3;
c) 24,088*10 la puterea 23 molecule N2;
d) 24,088*10 la puterea 26 molecule NH3.

Answer 1

a)1g N2=0,03571 moli N2
V = 0,03571 * 22,4 = 0,8 litri N2
b)1 g NH3=0,05882 moli NH3
V = 0,05882 * 22,4 = 1,31757 litri NH3
c)24,088 * 10 la 23 molecule = 4 moli N2 (imparti acest numar la nr lui Avogadro 6,022 * 10 la 23 si obtii 4) V = 4 * 22,4 = 89,6 litri N2
d)24,088 * 10 la 26 molecule = 4000 moli NH3 (la fel,imparti la N Avog)
V = 4000 * 22,4 = 89,6 m cubi NH3