Question

Calculati cit mai simplu 24 intregi 4pe5 +(8intregi 3pe11+5intregi 1pe5) asta e pagina 114 ex 4 culegere clasa 5

Answer 1

24 intregi 4/5 + ( 8 intregi 3/11 +  5 intregi 1/5 ) =

= 124/5 + ((8+5) + (3/11+1/5 )) =

= 124+ (13+26/55 ) =

= 124/5 +  13 intregi 26/55 =

= 124/5 + 741/55 = 

=  (1364+741)/55 = 

= 2105/55 = 421/11

Answer 2

24 intregi si 4/5 = ( 24 x 5 + 4) / 5 = 124 /5 
8 intregi si 3/11 = ( 8 x 11 + 3) /11= 91/11
5 intregi si 1/5 = ( 5 x 5 + 1) / 5 = 26/5

= 124/5 + ( 91/11 + 26 / 5 ) =  → cmmmc al numerelor (11, 5) = 55
= 124/5 + [ ( 5×91) / 55 + ( 11×26) /55]= → amplific fractiile din paranteza 
= 124/5 + ( 455/55 + 286/55) =
= 124/5 + 741/55=
=(11 × 124)/55 + 741/55= 
= 1 364/55 + 741/55 = 
= 1 105 /55 =  → simplific cu 5
= 221/11
= 20 intregi si 1/11=
= 20,(09)