Question

calculati cit mai simplu $\sqrt{68 ^{2} } } -32 ^{2}$ (totul sub radical)

Answer 1

radical(68^2-32^2)=radical[(2^2*17)^2 -(2^5)^2]=
radical[2^4*17^2- 2^10]=
radical[2^4(17^2-2^6)]=
radical[2^4(289-64)]=
radical[2^4*225]      =
radical[2^4*15^2]     = 2^2*15=60