Question

calculati compozitia procentuala a apei

Answer 1

$H_{2}O$
μH2O= 2*1+1*16=18g./mol

In 18 g. H2O se gasesc 2 g. H2 si 16g. O2.

18g. H2O......2g.H2.......16g.O2
100g. H2O.....x g. H2.....y g. O2

x=$\frac{2*100}{18}$
x=11.11g. H2

y=$\frac{16*100}{18}$
y=88.88g. O2

⇒11.11% H2 si 88.88% O2