Question

Calculati compozitia procentuala a hidroxidului de aluminiu

Answer 1

Al(OH)3=hidroxid de aluminiu
masa molară:A(Al)+3A(O)+3A(H)
M=27+3•16+3•1=78g/mol

78g Al(OH)3........27g Al......48g O.......3g H
100g Al(OH)3....... X g Al......Y g O.......Z g H
=>X=34,61% Al Y=61,53% O Z=3,86% H

A(..)=masa atomica
M=masa molară