Question

calculati compozitia procentuala a hidroxidului de cupru. mase atomice: cu:64 o:16 h:1

Answer 1

Cu(OH )2

Compozitie procentuala prin masa moleculara

M=64+2.16+2=98------>1mol=98 g

daca in 98g Cu(OH)2 se afla 64 g Cu ,32g O, 2g H atunci in 100 g se afla x,y,z.

98gCu(OH)2-----------64 g Cu---------32g O-----------2gH

100g------------------------x---------------------y----------------z

x=100.64:98=65,30 la suta Cu

y=100.32:98=32,65 la suta O

z=100.2:98=2,04 la suta H