Question

calculati compozitia procentuala a NaOH Ca(OH)2 si KOH

Answer 1

Masa moleculara a NaOH = 23 +16 +1=40

Consideram 40 ……………………..100%

                      23 ……………………….x%

                      16………………………y%

                      1………………………..z%

De aici scoatem fiecare necunosctuta astfel:

X=23*100/40=57,5% Na

Y=16*100/40=40%O

Z=1*100/40=2,5%H

La fel facem si pt Ca(OH)2

Masa molecular: 23+2*(16+1)=57

57…………………………….100%

23……………………………..x%

2*16…………………………y%

2*1……………………………z%

 

X=(23*100)/57=40,35 % Ca

Y=(2*16*100)/57=56,14%O

Z=(2*1*100/57)=3,50%H

 

 

Masa molecular KOH= 39+16+1=56

56………………………………100%

39………………………………..x%

16……………………………… y%

1…………………………………. Z%

 

X=(39*100)/56=69,64%

Y=(16*100)/56=28,57%

Z=(1*100)/56=1,78%