Question

Calculati compoziția procentuală masica a apei ( H2O)

Answer 1

[tex]M_{H_2O}=2+16=18g/mol M_{H}=1g/mol M_{O}=16g/mol [/tex]

[tex]H_2=\frac{1*2}{18}*100=\frac{200}{18}=11,11 [/tex]%

$O_2=\frac{16}{18}*100=\frac{1600}{18}=88,88$%