Question

Calculati compozitia procentuala pt urmotoci ostati
a) H₂ PO4
b) NaOH​

Answer 1

Răspuns:

Explicație:

a.    H3PO4

M= 3 +31 +4.16=98 ------> 98g/moli

98g H3PO4--------3gH--------31gP-------64g O

100g-----------------------x--------------y-----------z

x= 100 . 3 : 98 = 3,06% H

y= 100 . 31 : 98 =  31,63%P

z= 100 . 64 : 98 = 65,31% O

b .   NaOH

M= 23 +16 +1=40-------> 40g/moli

40g NaOH ------23g Na--------16gO--------1gH

100g---------------------x-------------y----------------z

x= 100. 23 : 40= 57,5% Na

y= 100. 16 : 40=40% O

z= 100.1 : 40=2,5% H