Question

.Calculati concentratia molara pentru solutia de HCl de concentratie 36,5% si p =1,183 g cm3

Answer 1

Cp=36.5%
ro(p-densitatea)=1.183g/cm3

Consider V=1L=1000cm3

Din ro deduc ms==>ro=ms/V==>ms=ro*V=1.183g/cm3*1000cm3=1183g

Din Cp deduc md==> Cp=md/ms*100==>md=Cp*ms/100=36.5*1183/100=431.795g

Deduc Cm==> Cm=md/M*Vs(L)=431.795/36.5*1=11.83 moli/L

MHCl=36.5g/mol

sau

n=m/M=11.83 moli HCl

Cm=n/Vs=11.83/1=11.83 moli/L

Am notat "*" Inmultire si "/" linia de fractie..