Question

calculati cu delta3x la puterea2 plus 5x minos2 estegal cu 0

Answer 1

3x³+5x-2=0
a=3
b=5
c=-2
∆=b²-4ac=5²-4*3*(-2)=25+24=49

x1=(-b-√∆)/2a=(-5-√49)2*3=(-5-7)/6=-12/6=-2

x2=(-b+√∆)2a=(-5+√49)/2*3=(-5+7)/6=2/6=1/3

S={-2;⅓}