Question

Calculati:
d) $log_{2} 4\sqrt{2}/\sqrt[3]{2}$

Answer 1

$\it \dfrac{4\sqrt2}{\sqrt[3]{\it2}}=2^2\cdot2^{\frac{1}{2}}:2^{\frac{1}{3}}=2^{2+\frac{1}{2}-\frac{1}{3}}=2^{\frac{13}{6}}\\ \\ \\ Expresia\ \ devine:\\ \\ \\ log_2 2^{\frac{13}{6}}=\dfrac{13}{6}\cdot log_22=\dfrac{13}{6}\cdot1=\dfrac{13}{6}$