Question

calculati!
Dau 150 puncte!
Va rog!

Answer 1

a)-$\sqrt{3}$($\sqrt{12}$+$\sqrt{3}$=

=-$\sqrt{36\\}$-3

=-6-3=-9

b)$\sqrt{6}$($\sqrt{24}$-$\sqrt{6}$)=

=$\sqrt{144}$-6

=12-6=6

c)(√8+√5)(√8-√5)=

=8-5=3

d)(2-$\frac{\sqrt{3} }{4}$)(2+$\frac{\sqrt{3} }{4}$=

=2²-($\frac{\sqrt{3} }{4}$)²

=4-$\frac{3}{16}$

amplifici pe 4

=$\frac{16-3}{16}$

=$\frac{13}{16}$