Matematică, întrebare adresată de vladcopoiu, 8 ani în urmă

calculati dau coroana

Anexe:

Răspunsuri la întrebare

Răspuns de Andy062
1

Răspuns:

a) \sqrt{4\sqrt{2} \cdot25\sqrt{8} }

=\sqrt{4\sqrt{2} \cdot25\cdot2\sqrt{2} } \\\\=\sqrt{4\cdot2\cdot25\cdot2} \\\\=\sqrt{400} \\\\\boxed{=20}

b) \sqrt{10\sqrt{15} : (2\sqrt{5}) \cdot 125\sqrt{27} }

=\sqrt{\sqrt{3}\cdot125\cdot3\sqrt{3} } \\\\=\sqrt{5\cdot3\cdot125\cdot3} \\\\ =\sqrt{5625} \\\\\boxed{=75}

c) \sqrt{2\sqrt{3}:(4\sqrt{6})\cdot18\sqrt{2} \cdot\sqrt{6} \cdot9\sqrt{6} }

=\sqrt{\frac{2\sqrt{3} }{4\sqrt{6} } \cdot18\sqrt{2}\cdot6\cdot9} \\\\=\sqrt{\frac{1}{2\sqrt{2} } \cdot18\sqrt{2}\cdot6\cdot9} \\\\=\sqrt{1\cdot9\cdot6\cdot9} \\\\=\sqrt{486} \\\\\boxed{=9\sqrt{6}}

d) \sqrt{\frac{12\sqrt{6}}{3}\cdot \frac{\sqrt{6}}{9}\cdot6^{-1}  }

=\sqrt{4\sqrt{6}\cdot\frac{\sqrt{6}}{9}\cdot6^{-1}  } \\\\=\sqrt{\frac{4\sqrt{6}\cdot\sqrt{6}\cdot6^{-1}}{9} } \\\\=\sqrt{\frac{4\cdot6^{1}\cdot6^{-1}}{9} } \\\\=\sqrt{\frac{4\cdot6^{1-1}}{9} } \\\\=\sqrt{\frac{4\cdot6^{0}}{9} } \\\\=\sqrt{\frac{4}{9} } \\\\\boxed{=\frac{2}{3} }

Sper ca te-am ajutat!

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