Question

Calculați:
Dau coroana!!!
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Answer 1

Explicație pas cu pas:

a)

$2 \sqrt{3} \cdot 4 \sqrt{6} = 8 \sqrt{ {3}^{2} \cdot 2} = 8 \cdot 3 \sqrt{2} = 24 \sqrt{2}$

b)

$2 \sqrt{3} \cdot ( - \sqrt{2}) = - 2 \sqrt{3 \cdot 2} = - 2 \sqrt{6}$

c)

$- \dfrac{2 \sqrt{2} }{3} \cdot \dfrac{ \sqrt{2} }{4} = - \dfrac{2 \sqrt{ {2}^{2} } }{3 \cdot 4} = - \dfrac{2 \cdot 2}{3 \cdot 4} = - \dfrac{1}{3}$

d)

$( - 2 \sqrt{3}) \cdot \bigg( - \dfrac{ \sqrt{3} }{2} \bigg) = \dfrac{ 2\sqrt{ {3}^{2} } }{2} = \dfrac{ 2 \cdot 3 }{2} = 3$

e)

$- 4 \sqrt{3} \cdot \sqrt{7} = - 4 \sqrt{21}$

f)

$6 \sqrt{5} \cdot \bigg( - \dfrac{ \sqrt{5} }{30} \bigg) = - \dfrac{ 6 \cdot \sqrt{ {5}^{2} } }{30} = \dfrac{ 6 \cdot 5 }{30} = \dfrac{30}{30} = 1$

g)

$1.(4) \sqrt{75} \cdot ( - 2.4 \sqrt{50}) \cdot \bigg( - \dfrac{1}{26} \sqrt{18} \bigg) = \\ \dfrac{14 - 1}{9} \cdot 5 \sqrt{3} \cdot \bigg( - \dfrac{24 \cdot 5 \sqrt{2} }{10}\bigg) \cdot \bigg( - \dfrac{ 3\sqrt{2} }{26}\bigg) \\ = \dfrac{13 \cdot5 \sqrt{3} \cdot 24 \cdot 5 \sqrt{2} \cdot 3 \sqrt{2} }{9 \cdot 10 \cdot 26} = 20 \sqrt{3}$