Question

Calculati
Dau coroana​

Answer 1

Explicație pas cu pas:

${\bigg( \dfrac{9}{4}\bigg)}^{6} \cdot {\bigg( \dfrac{3}{2}\bigg)}^{9} = {\bigg( \dfrac{ {3}^{2} }{ {2}^{2} }\bigg)}^{6} \cdot {\bigg( \dfrac{3}{2}\bigg)}^{9} = \\ = {\bigg({\bigg( \dfrac{3}{2}\bigg)}^{2}\bigg)}^{6} \cdot {\bigg( \dfrac{3}{2}\bigg)}^{9} = {\bigg( \dfrac{3}{2}\bigg)}^{2 \cdot 6} \cdot {\bigg( \dfrac{3}{2}\bigg)}^{9} \\ = {\bigg( \dfrac{3}{2}\bigg)}^{12} \cdot {\bigg( \dfrac{3}{2}\bigg)}^{9} = {\bigg( \dfrac{3}{2}\bigg)}^{12 + 9} = {\bigg( \dfrac{3}{2}\bigg)}^{21}$

Answer 2

$\displaystyle \Bigg(\frac{9}{4}\Bigg)^6 \cdot \Bigg(\frac{3}{2}\Bigg)^9= \Bigg( \Bigg(\frac{3}{2} \Bigg)^2\Bigg)^6 \cdot \Bigg(\frac{3}{2} \Bigg)^9=\Bigg(\frac{3}{2} \Bigg)^{12}\cdot \Bigg(\frac{3}{2} \Bigg)^9=\Bigg(\frac{3}{2} \Bigg)^{12+9}=\Bigg(\frac{3}{2} \Bigg)^{21}$