Question

Calculati derivata acestui exercitiu.

Answer 1

$( {ln}^{2} x - ln {x}^{2} + 1)'$

$= ( {ln}^{2} x)' - (ln {x}^{2} )' + 1'$

$= 2lnx \times (lnx)' - (2lnx)' + 0$

$= 2lnx \times \frac{1}{x} - 2 \times (lnx)'$

$= \frac{2lnx}{x} - 2 \times \frac{1}{x}$

$= \frac{2lnx}{x} - \frac{2}{x}$

$= \frac{2lnx - 2}{x}$

$= \frac{2(lnx - 1)}{x}$