Question

calculati detaliat va rog mult)))
radical 1intreg si 3 pe 36 *(inmultit)radical 1 intreg 10 pe 39 +radical din 48 pe radical din 3

Answer 1

√[(1*36+3)/36]*√[(1*39+10)/39]+√(48/3)=
√(39/36)*√(49/39)+√16=
√39/√36*√49/√39+4=
1/√36*√49/1+4=
√49/√36+4=
7/6+4=
7/6+24/6=
31/6=5,1(6)