Question

Calculati diferenta numerelor a=2^0+2^1+2^2+2^3+....2^1997. ; b=64^333-1

Answer 1

B= ((2^6)^333) - 1= (2^1998)-1; a-b= 1-1+(2^1+2^2+...+2^1997)- 2^1998= 2*(((2^1997)-1)/(2-1)) = 2^1998-2^1998 -2= -2