Question

calculati
E=0,4(76)+2,(4)+4,0(9) pe 2,(35)+5,(63)+6,0(72)

Answer 1

0,4(76)=(476-4)/990=472/990
2,(4)=(24-2)/9=22/9
4,0(9)=(409-40)/90=369/90
2,(35)=(235-2)/99=233/99
5,(63)=(563-5)/99=558/99
6,0(72) =(6072-60)/990=6012/990

E=[0,4(76)+2,(4)+4,0(9) ]/[ 2,(35)+5,(63)+6,0(72) ]=
=(472/990+22/9+369/90)/(233/99+558/99+6012/990)=
=(472+2420+4059)/990 × 990/(2330+5580+6012)
=6951/13922=0,499281...



E=[0,4(76)+2,(4)+4,0(9) ]/[ 2,(35)+5,(63)+6,0(72) ]=
=7,0(21)/14,0(62)=0,499281...