Question

Calculati ecuatia:

(2^20 x 3^20) :6^19 - 9^5 :27^3 +11^20 :11^19=

Answer 1

$( {2}^{20} \times {3}^{20} ) \div {6}^{19} - {9}^{5} \div {27}^{3} + {11}^{20} \div {11}^{19}$

$= {(2 \times 3)}^{20} \div {6}^{19} - { ({3}^{2} )}^{5} \div {( {3}^{3} )}^{3} + {11}^{20 - 19}$

$= {6}^{20} \div {6}^{19} - {3}^{2 \times 5} \div {3}^{3 \times 3} + {11}^{1}$

$= {6}^{20 - 19} - {3}^{10} \div {3}^{9} + 11$

$= {6}^{1} - {3}^{10 - 9} + 11$

$= 6 - {3}^{1} + 11$

$= 6 - 3 + 11$

$= 3 + 11$

$= 14$

Answer 2

= 6²⁰ ÷6¹⁹ − 3¹⁰ ÷ 3⁹ + 11²⁰ ÷11¹⁹

= 6 − 3+11= 14