Question

calculati ecuatia 2x^2-8x+3=0

Answer 1

Răspuns:

Explicație pas cu pas:

2x² - 8x + 3 = 0

a = 2

b = - 8

c = 3

Δ = b² - 4ac = (-8)² - 4×2×3 = 64 - 24 = 40

x1 = (-b + √Δ)/2a = (8 + √40) / 4 = (8+2√10)/4 = 2(4+√10)/4 = (4+√10)/2

x2 = (-b - √Δ)/2a = (8 - √40) / 4 = (8-2√10)/4 = 2(4-√10)/4 = (4 -√10)/2

X = { (4+√10)/2 ; (4 -√10)/2 }

Answer 2

2x²-8x+3=0

Δ=b²-4ac=(-8)²-4*2*3=64-24=40

x₁,₂=(-b±√Δ)/2a=(8±√40)/4=(8±2√10)/4=(4±√10)/2

x₁=(4+√10)/2

x₂=(4-√10)/2

S={(4±√10)/2}