Question

Calculați f'(x)


$f(x) = xe {}^{x} - e ^{x} + 1$

Answer 1

f(x)=1*e^x+xe^x-e^x+0=e^x+xe^x-e^x=xe^x

Answer 2

f ' ( x ) = (xeˣ)' - (eˣ)' + (1)'
f ' ( x ) = x'eˣ + x(eˣ)' - eˣ + 0
f ' ( x ) = 1 · eˣ + xeˣ - eˣ
f ' ( x ) = eˣ + xeˣ - eˣ
f ' ( x ) = xeˣ