Question

calculați folosind formulele de calcul prescurtat:
a) (2+√2) ^2-(2√2-3) ^2
b) (3-√3) ^2+(√3+2) ^2
c) (√3-1) ^2+(2√3+1) ^2
d) (2√3-1) ^2-(2√2-1)×(2√2+1)
e) (2√3+3)×(2√3-3)-(√2-1)×(√2+1)
f) (3-√6)×(3+√6)+(√3-1)×(√3+1)-(3-√5)×(3+√5)
g) (4-2√5)×(4+2√5)+(3√2-5)×(3√2+5)-(√6+√2)×(√6-√2)
URGENT va roggg ​

Answer 1

Răspuns:

Explicație pas cu pas:

a) (2+√2)²-(2√2-3)²=[(2+√2-2√2+3)(2+√2+2√2-3}]=(5-√2)(3√2-1)

b) (3-√3) ²+(√3+2) ²=9-6√3+3+3+4√3+4=19-2√3

c) (√3-1) ²+(2√3+1) ² =3-2√3+1+12+4√3+1=17+2√3

d) (2√3-1) ²-(2√2-1)×(2√2+1) =12-4√3+1-8+1=6-4√3

e) (2√3+3)×(2√3-3)-(√2-1)×(√2+1) =12-9+2-1=14-10=4

f) (3-√6)×(3+√6)+(√3-1)×(√3+1)-(3-√5)×(3+√5) =9-6+3-1-9+5=8-7=1

g) (4-2√5)×(4+2√5)+(3√2-5)×(3√2+5)-(√6+√2)×(√6-√2)=

=16-20+18-25+6-2=16+18+6-20-25-2=40-47=-7