Question

calculati folosind metoda factorului comun : 3^n+3x4^n+3^n+1x4^n+2-3^n+2x4^n+1

Answer 1

3^n+3×4^n+3^n+1×4^n+2-3^n+2×4^n+1=3^n(1+3×1^n+1×1^n)+2-3^n(1+2×1^n)+1=3^n(5×1^n×1^n)+3-3^n(3×1^n)=3^n(5×1×1)+3-3^n(3×1)=3^n×5+3-3^n×3=3^n(1×5+3-1×3)=3^n×(5+3-3)=3^n(5+3-3)=
3^n×5