Question

Calculati folosind metoda mersului invers pe operatii va rog : 6-5:[4-3:(2-2:x)] egal 1

Answer 1

6-5:[4-3:(2-2:x)]=1

5:[4-3:(2-2:x)]=1+6

4-3:(2-2:x)=7×5

3:(2-2:x)=35+4

2-2:x=39×3

2:x=117×2

x=234

Sper sa te ajute

:))

Daca poti si sa imi dai coroana, ar fi foarte tare

;)

Answer 2

6-5:[4-3:(-2:x)]=1 5:[4-3:(2-2:x)]=6+1=7 [4-3:(2-2:x)]=7×5=35 3:(2-2:x)=35-4=36 (2-2:x)=36×3=108 2:x=108+2 2x=120 x=120:2 x=60