Question

calculați: h) 2^5-3•[3•7-2•(6^2-2^3):4]+1^123​

Answer 1

Răspuns:

2⁵-3•[3•7-2•(6²-2³):4]+1¹²³=

32-3·[21-2·(36-8):4]+1=

32-3·(21-2·28:4)+1=

32-3·​(21-14)+1=

32-3·7+1=

32-21+1=

11+1=

12

Answer 2

Răspuns:

12

Explicație pas cu pas:

$2^5-3\cdot[3\cdot 7-2\cdot (6^2-2^3):4]+1^{123}=$

$=32-3\cdot[21-2\cdot (36-8):4]+1$

$=32-3\cdot(21-2\cdot 28:4)+1$

$= 32-3\cdot (21-2\cdot7)+1$

$= 32-3\cdot (21-14)+1$

$= 32-3\cdot 7+1$

$= 32-21+1$

$= 11+1$

$= 12$