Question

Calculati: i)7^0+1^10+7^1-0^2009; ii) 7×2^1997-6×2 ^1996-2×2^1998​

Answer 1

Răspuns:

• i) 9
• ii) 0

Explicație pas cu pas:

i) 7^0 + 1^10 + 7^1 - 0^2009 =

1 + 1 + 7 - 0 =

2 + 7 =

9

ii) 7 × 2^1997 - 6 × 2^1996 - 2 × 2^1998 =

7 × 2^1997 - 3 × 2 × 2^1996 - 2^1999 =

7 × 2^1997 - 3 × 2^1997 - 2^1999 =

(7 - 3 - 2²) × 2^1997 =

(7 - 3 - 4) × 2^1997 =

0 × 2^1997 =

0

Answer 2

Răspuns:

1)

$7^{0} +1^{10} +7^{1} -0^{2009} = \\\\1+1+7-0 =\\\\9$

2)

$7*2^{1997}-6*2^{1996}-2*2^{1998}=\\\\ 7*2^{1997}-3*2*2^{1996}-2^{1999}=\\\\7*2^{1997}-3*2^{1997}-2^{2}* 2^{1997}=\\\\(7-3-4)*2^{1997}=\\\\0* 2^{1997}=\\\\0$