Question

Calculati : ì) 8^16:(2*2^4*2^10)^3-2^1-2^0

Answer 1

$8^{16}:(2*2^4*2^{10})^3-2^1-2^0=(2^3)^{16}:(2^5*2^{10})^3-2-1=2^{48}:(2^{15})^3\\-2-1=2^{48}:2^{45}-3=2^3-3=8-3=5$

Answer 2

8^16:(2*2^4*2^10)^3-2^1-2^0 = 8^16:2^(1+4+10)^3-2-1 = 8^16:2^45-3 = ((2)^3)^16:2^45-3 = 2^48:2^45-3 = 2^3-3 = 8-3 =5