Matematică, întrebare adresată de andreea9713, 8 ani în urmă

calculati in doua moduri:
a)
( -\frac{4}{3} ) \times ( -  \frac{5}{8}  +  \frac{1}{4} )
b)
 \frac{37}{25}  \times ( \frac{7}{5}  -  \frac{3}{20}
c)
 -2 \times \frac{1}{2}  \times ( -  \frac{1}{2}  -  \frac{3}{5}
d)
0.75 \times ( -  \frac{7}{3}  +  \frac{5}{6}
e)
2.25 \times ( -  \frac{1}{7}  +  \frac{1}{21}
f)
 - 1.1  \times ( \frac{3}{11}  -  \frac{1}{22}
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Răspunsuri la întrebare

Răspuns de pav38
7

Răspuns:

a)

(-\frac{4}{3} )* (-\frac{5}{8}+\frac{1}{4}) =  (-\frac{4}{3} )* (-\frac{5}{8})+(-\frac{4}{3})*\frac{1}{4} = \frac{5}{6} -\frac{1}{3} =\frac{5-2}{6}=\frac{3}{6} =\frac{1}{2}  \\\\(-\frac{4}{3} )* (-\frac{5}{8}+\frac{1}{4}) =(-\frac{4}{3} )*(\frac{-5+2}{8} )=(-\frac{4}{3} )*(\frac{-3}{8})=\frac{1}{2}

b)

\frac{37}{25}*(\frac{7}{5}-\frac{3}{20})=\frac{37}{25}*\frac{7}{5}- \frac{37}{25}* \frac{3}{20} =\frac{37*7}{125}-\frac{37*3}{500}=\frac{37*7*4-37*3}{500}=\frac{1036-111}{500} =\frac{945}{500}=\frac{37}{20}    \\\\\frac{37}{25}*(\frac{7}{5}-\frac{3}{20}) =\frac{37}{25}*\frac{28-3}{20}=\frac{37}{20}

d)

0,75 * (-\frac{7}{3} +\frac{5}{6}) = 0,75 * (-2,333 +0,833) = 0,75 * (-1,497) = - 1,13\\\\0,75 * (-\frac{7}{3} +\frac{5}{6}) = \frac{75}{100} *(-\frac{7}{3})+\frac{75}{100}*\frac{5}{6}=\frac{3}{4} *(-\frac{7}{3})+\frac{3}{4}*\frac{5}{6}=-\frac{7}{4} +\frac{5}{8} = \frac{-14+5}{8} =-1,13

restul ai in atasament

Anexe:
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