Question

calculati in triunchi:e)873x3x0+425:5:5= f)400:8:2+40x5+63x11= g)990+5+0x662+1:1= h)11+7x121-60x8= i)275+625:5= j)200-4x13-5x15= k)600-27x20+18:3=

Answer 1

e)873x3x0+425:5:5=
   2619x0+85:5=
   0+17=17
f)400:8:2+40x5+63x11=
   50:2+200+693=
   25+893=918
g)990+5+0x662+1:1=
   995+0+1=996
h)11+7x121-60x8=
   11+847-480=
   11+367=378
i)275+625:5=
  275+125=400
j)200-4x13-5x15=
  200-52-75=
  148-75=73
k)600-27x20+18:3=
   600-540+6=
   60+6=66

Answer 2

e)873x3x0+425:5:5=
= 2619x0+85:5
= 0+17
=17
f)400:8:2+40x5+63x11=
=50:2+200+423
=25+200+423
=225+423
= 648
g)990+5+0x662+1:1=
=990+5+0+1
=995+0+1
=995+1
=996
h)11+7x121-60x8=
=11+847-480
=858-480
=378
i)275+625:5=
=275+125
=400
j)200-4x13-5x15=
=200-52-75
=148-75
=73
k)600-27x20+18:3=
=600-540+6
=60+6
=66
te rog frumos îmi dai coronița.