Question

Calculati. (Liceu). Multumesc!​

Answer 1

Explicație pas cu pas:

x²+2x-3>=0 =>

x²+3x-x-3>=0 =>

x(x+3)-1(x+3)>=0 =>

(x+3)(x-1)>=0

Avem 2 cazuri:

x+3>=0 =>x>=-3

x-1>=0=>x>=1

=>x€[1,+infinit)

Sau

x+3<=0 => x<=-3

x-1<=0=>x<=1

=>x€(-infinit,-3]

=>x€[1,+infinit)U(-infinit,-3]