Question

Calculati limitele laterale (care au sens )in punctele mentionate pentru urmatoarele functii:
f:R\{1 pe 2} cu valori in R,f(x)=x/(2x-1)^2 in x=1 pe 2

Answer 1

Ls:x--.>1/2 x<1/2  lim f(x)=limx/(2x-1)^2=(1/2)/(2*(1/2-0)-1)^2=

(1/2)/((1-0-1)^2=1/2*((-0)^2=1/+0=+infinit

LD: x-->1/2   x>1/2 limf(x)=lim x/(2x-1)^2=(1/2)/[(1+0)-1]^2=(1/2)/(1+0-1)^2=1/2*(+0)^2=1/+0=+infinit

Ls=Ld=+infinit