Question

Calculati log in baza 1\3 din 9.

Answer 1

log(1/3)9=log(1/3)3²=2*log(1/3)3=2*log(1/3)3^(-1)=-2

Answer 2

$\it log_{\dfrac{1}{3}}9 =\dfrac{log_39}{log_3{\dfrac{1}{3}}} =\dfrac{log_3 3^2}{log_3 3^{-1}} = \dfrac{2}{-1} =-2$