Question

Calculati
[log in baza 2 din 7]+[1,6]

Answer 1

[tex]\text{Presupunand ca [] inseamna parte intreaga,mai intai sa observam ca:}\\ 4\ \textless \ 7\ \textless \ 8,\text{iar din monotonia functiei logaritm obtinem:}\\ 2\ \textless \ \log_2 7\ \textless \ 3\Rightarrow [\log_2 7]=2\\ \text{Prin urmare:}\\ {[\log_2{7}]+[1,6]}= 2+1=\boxed{3}[/tex]

Answer 2

$\it log_2 4 \ \textless \ log_2 7 \ \textless \ log_2 8 \Rightarrow 2\ \textless \ log_2 7 \ \textless \ 3 \Rightarrow [log_2 7] =2$

[1,6] = 1

$\it [log_2 7] + [ 1,6 ] = 2+ 1=3$